Which situation can be modeled by the inequality 60 – 15x > 7?

one situation could be:

you have a total of $60 to spend. at a certain store, shirts cost 15 dollars each. what is the maximum number of shirts you can buy if you want to have more than 7 dollars left over in your pocket?

of course there are infinitely many possible ways to answer this open-ended question.

further explanation:

let x be the number of shirts we buy. this means x is a positive whole number. if each shirt costs $15, then buying x of them leads to a total cost of 15*x = 15x dollars.

this expression of 15x is subtracted from our budget of 60 to get 60-15x

the expression 60-15x represents how much money is left over. we want this to be greater than 7 dollars,

so we write 60-15x > 7 as a way of mathematically stating the prior sentence.

let's solve for x.

60 - 15x > 7

60 - 15x+15x > 7+15x add 15x to both sides

60 > 7+15x

60-7 > 7+15x-7 subtract 7 from both sides

53 > 15x

15x < 53

15x/15 < 53/15 divide both sides by 15

x < 3.53

since x is a whole number, this is the same as saying

therefore, the maximum number of shirts you can buy is 3

if you bought 3 shirts, then 60-15*x = 60-15*3 = $15 is left over

if you bought 4 shirts, then 60-15*x = 60-15*4 = $0 is left over

this verifies that 3 is the largest x can get.

38 was the other number of your question.

yes, whats the problem?