Atortoise and a hare are competing in a 2000-meter race. the arrogant hare decides to let the tortoise have a 510-meter head start. when the start gun is fired the hare begins running at a constant speed of 8 meters per second and the tortoise begins crawling at a constant speed of 5 meters per second. define a function f to represent the tortoise's distance from the finish line (in meters) in terms of the number of seconds t since the start of the race.

The distance covered by the hare and the tortoise in t seconds are 8t and 5t respectively. (Simple Speed-Distance-Time relation)

The tortoise gets a 510m headstart so at t=0 is 1490m.

The functions representing the distance of both of them from the finish line is,

F(x)=2000-8t,. for hare

G(x)=1490-5t,. for tortoise

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.