Anybody me this is so hard that not even i can't solve this i don't pay attention in class

Step-by-step explanation:

Given:

bisects angle BAC

Triangle ABC is isosceles triangle, because Angles adjacent to the base of isosceles triangle ABC are congruent.

Hence,

The sum of the measures of all interior angles is 180°, so,

Since bisects angle BAC, angles BAD and CAD are congruent by definition of angle bisector. So,

AD ia angle bisector in isosceles triangle drawn to the base, so it is the height. Thus, AD and BC are perpendicular. So,

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true