Aresearch firm conducted a survey to determine the mean amount americans spend on coffee during a week. they found the distribution of weekly spending followed the normal distribution with a population standard deviation of $5. a sample of 64 americans revealed that x¯¯¯=$20 . what is the 95% confidence interval estimate of μ?

95% confidence Interval would be between $18.775 and $20.225.

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

And margin of error (ME) around the mean calculated as

ME= where

Using the numbers, we get:

ME= =1.225

Then 95% confidence Interval would be 20±1.225 or between $18.775 and $20.225

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

answer: get a conversion sheet out i dont know the exact measurments

step-by-step explanation: divide the number of feet with the nu,ber of milrs and there your answer