Solve the system of equations:

x = 2uy - 8

4x + y = 13

a)x = 2 and y = -5

b)x = 2 and y = 5

c)x = -2 and y = -5

d)x = -2 and y = 5

Step-by-step explanation:

{x = 2y - 8

{4x + y = 13

13 = 4[2y - 8] + y

13 = 8y - 32 + y

13 = −32 + 9y

+ 32 + 32

____________

[Plug this back into both equations above to get the x-coordinate of 2];

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see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

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