14. you start an investment account with $3000 and save $100 each month. write a
rule to represent the total amount of money you invest into your account as an
arithmetic sequence. how much money will you have invested after 12 months?

4200

Step-by-step explanation:

In an arithmetic sequence equation t=a + (n-1)d, a is the starting value. In this case, a=3000.

Although, since the initial investment is not considered the first month, the equation is t = a + dn.

d is the rate of change. In this case, the rate of change is 100 for every month, n.

Substitute these values from the problem to get an equation:

t = 3000 + 100n

t means the total amount of money we have for the amount of months (n) that passed.

Sub n for 12.

t = 3000 + 100n

t = 3000 + 100(12)

t = 4200

You will have $4200 after 12 months of investment.

the answer is 0.000652422

but if you ment to ask what is 6131 divided by 4, it is 1532.75.

step-by-step explanation:

i dont understand

step-by-step explanation: