In the 1990s the demand for personal computers in the home went up with household income. for a given community in the 1990s, the average number of computers in a home could be approximated by q = 0.3458 ln x − 3.045 10,000 ≤ x ≤ 125,000 where x is mean household income. a certain community had a mean income of $30,000, increasing at a rate of $1,000 per year.
a. how many computers per household were there? (round your answer to four decimal places.) 0.5198 correct: your answer is correct. computers per household.
b. how fast was the number of computers in a home increasing? (round your answer to four decimal places.) 0.0115 correct: your answer is correct. computers per household per year.

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ;   10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, = $1,000

Now,

a) computers per household are

since,

mean income of  $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

or

q = 0.5198 computers per household

b) Rate of increase in computers i.e

=

or

on substituting the values, we get

or

= 0.01153 computers

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

idk

step-by-step explanation: