Mathematics, 23.11.2019 01:31, mrashrafkotkaat
Acommon inhabitant of human intestines is the bacterium escherichia coli. a cell of this bacterium in a nutrient-broth medium divides into two cells every 20 minutes. the initial population of a culture is 57 cells.
(a) find the relative growth rate. (assume t is measured in hours.)
k = ln(8)
(b) find an expression for the number of cells after t hours.
p(t) = 57(8)^t
(c) find the number of cells after 8 hours.
956,301,312 cells.
(d) find the rate of growth after 8 hours. (round your answer to three decimal places.)
cells per hour
(e) when will the population reach 20,000 cells? (round your answer to two decimal places.)
Answers: 2
Mathematics, 21.06.2019 19:30, gabby77778
[15 points]find the least common multiple of the expressions: 1. 3x^2, 6x - 18 2. 5x, 5x(x +2) 3. x^2 - 9, x + 3 4. x^2 - 3x - 10, x + 2 explain if possible
Answers: 3
Mathematics, 21.06.2019 22:10, bigboss3026
Which of the following circles have their centers in the third quadrant?
Answers: 2
Acommon inhabitant of human intestines is the bacterium escherichia coli. a cell of this bacterium i...
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