Suppose a bag contains 4 white chips and 6 black chips. what is the probability of randomly choosing a black chip, not replacing it, and then randomly choosing another black chip?

a. 9/25
b. 4/25
c. 1/3
d. 2/15

Option C

The probability of randomly choosing a black chip, not replacing it, and then randomly choosing another black chip is

A bag contains 4 white chips and 6 black chips .

So, total number of chips are 10

We have to find the probability of randomly choosing a black chip, not replacing it, and then randomly choosing another black chip

Let A be the event of randomly choosing a black chip out of total 10 chips can be written as:-

Let B be the next successive event in which the black chip is not replaced, so we are left with 4 White chips and 5 Black Chips

Now the probability of happening this event is :

Since, these are successive cases so total probability is:

Hence, the probability of happening given event is

Thus option C is correct

4444444444444 i think

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w