The width of a rectangle is half as long as the
length. the rectangle has an area of 128 square
feet. what are the length and width of the
rectangle?
separate the answers with a comma.

The length of the rectangle is 16 feet, the width of the rectangle is 8 feet.

Step-by-step explanation:

1. Let's check the information given to resolve the question:

Length of the rectangle = x

Width of the rectangle = x/2 ( half as long as the  length)

Area of the rectangle = 128 square feet

2. Let's find the value of the length and the width

Area of the rectangle = Length of the rectangle * Width of the rectangle

128 = x * x/2

128 = x² /2 (x * x = x²)

256 = x² (Multiplying by 2 to both sides of the equation)

x² = 256

√x² = √ 256

x = 16

The length of the rectangle is 16 feet.

Width of the rectangle = x/2 = 16/2 = 8 feet.

The length of the rectangle is 16 feet, the width of the rectangle is 8 feet.

The rectangle has length = 16 feet, width = 8 feet

Explanation:

Let the length be x, we are given that width is half as long as the length so we can say that width is equal to x/2

We are given the area to be = 128 square feet ,

and we know area = length x breadth

So area =

=>

=> 256 =  

=> x = 16 = length

and width =

which are the required length and breadth of the rectangle

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

answer: howdy

step-by-step explanation: