Which of the following is the probability against a spinner landing on a green section if the spinner has 15 sections and 3 of them are green?

Step-by-step explanation:

The probability of an event , E, happening is:

P(E) = Number of E/ Total Number

Here, we are considering a spinner with sections in color. We want probability that spinner lands on green. So we will need:

Number of divisions of spinner that is green, and

Number of total divisions in the spinner

We will then divide.

Now, from the problem, we are told that there are a total of 15 divisions. And out of those 15, three of them are green, thus:

Number of divisions that are green = 3

Total number of divisions = 15

Thus, the probability would be [let "G" be the event that spinner lands on green]:

P(G) =

This is the probability.

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)