At 9: 00 on saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path. the bicyclist heading north is riding 6 km/hour faster than the bicyclist heading south. at 10: 15, they are 42.5 km apart. find the two bicyclists’ rates.

The rates of bicyclists of north and south are  20km/hr and 14km/hr respectively.

Step-by-step explanation:

Since we have given that

Let the speed of bicyclist heading south be 'x'.

Let the speed of bicyclist heading north be 'x+6'.

Since they are moving in opposite directions,

So, relative speed = x+x+6=2x+6

Time taken = 10: 15 to 9:00 = 1 hour 15 minutes =

Distance between them = 42.5 km

According to question, it becomes,

Speed of bicyclist heading north would be 14+6=20 km/hr

So, the rates of bicyclists of north and south are  20km/hr and 14km/hr respectively.

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step-by-step explanation:

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: