Financial accounting: tools for business decision making, ninth edition wileyplus custom course for the university of akron
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problem 11-08a (part level submission)
on january 1, 2022, indigo corporation had these stockholders' equity accounts.
common stock ($10 par value, 75,000 shares issued and outstanding)
paid-in capital in excess of par value
retained earnings
$750,000
490,000
700,000
sion)
during the year, the following transactions occurred.
study
jan. 15
feb. 15
apr. 15
may 15
dec. 1
dec. 31
declared a $0.60 cash dividend per share to stockholders of record on january 31, payable february 15.
paid the dividend declared in january
declared a 10% stock dividend to stockholders of record on april 30, distributable may 15. on april 15, the market price of the stock was $13 per share.
issued the shares for the stock dividend.
declared a $0.70 per share cash dividend to stockholders of record on december 15, payable january 10, 2023.
determined that net income for the year was $370,000.

answer:

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step-by-step explanation:

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !