Abaseball is thrown vertically upward at a rate of 65 feet per second from an initial height of 4 feet. use the projectile formula h = − 16 t 2 + v 0 t + h 0 to determine when the height of the ball will be 93 feet.

At time t = 2.03 s height of ball = 93 feet

Step-by-step explanation:

We have h(t) =  − 16 t² + v₀ t + h₀

A baseball is thrown vertically upward at a rate of 65 feet per second from an initial height of 4 feet.

Initial speed, v₀ = 65 ft/s

Initial height, h₀ = 4 ft

Substituting

             h(t) =  − 16 t² + 65 t + 4

Now we need to find time when h(t) = 93 ft

               93 =  − 16 t² + 65 t + 4

                 16 t² - 65 t + 89 = 0

                 t = 2.03 s  or  t = 2.03 s

At time t = 2.03 s height of ball = 93 feet

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