(1 point) write a triple integral including limits of integration that gives the volume of the cap of the solid sphere x2+y2+z2≤10 cut off by the plane z=1 and restricted to the first octant. (in your integral, use theta, rho, and phi for theta, and phi, as needed.)

i really dont know

step-by-step explanation:

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

10 b/c 5*2 =10

step-by-step explanation: