Specifications for the shaft of an electric motor indicate the diameter of the shaft must be within 0.5±0.01 inches to be considered non-defective. data from inspectors indicate that currently, shaft diameters follow a normal distribution with mean m=0.505 and standard deviation s=0.005.
a) what fraction of shafts will be defective?
b) suppose the mean shifts to m=0.5, now what fraction of shafts will be defective?
c) suppose the mean stays at m=0.5, and you want to reduce the standard deviation so that 99.9% of the shafts are non-defective. what value of s will produce the desired result?

1. she sold more on day 2 because if you turn .85 into a fraction{85/100} and you give 7/9 and 85/100 the same denominator{180} you can see which one has the bigger numerator and that one will be the most sold.

2. yes it is in simplest form, because if you look at 38 and 53 's greatest common factor, you cant find one so you cant reduce it

3. no, this is not a prime factorization because the numbers are not all prime numbers, the correct prime factorization is:   2 x 5 x 2

4.   in 12 days he will run and play trumpet again

work 4 4: 123123123123

                123412341234     in 12 days he will play the trumpet and run on the same day

step-by-step explanation:

i am normally pretty good at math, im new to this site, but im 1 grade ahead in my math, i luv math try my answers out, see how they work

histogram would be best to show the volunteer totals for each clinic and how they differ to each other.

your answer is false.

replace the variable (x) with -3. insert it using parenthesis like this:

-35(-3) = -105

this statement is false because -35 multiplied by -3 is 105, not -105.