Tutoring services: the community college survey of student engagement reports that 46% of the students surveyed rarely or never use peer or other tutoring resources. suppose that in reality 40% of community college students never use tutoring services available at their college. in a simulation we select random samples from a population in which 40% do not use tutoring. for each sample we calculate the proportion who do not use tutoring. if we randomly sample 100 students from this population, the standard error is approximately 5%. would it be unusual to see 46% who do not use tutoring in a random sample of 100 students?

No, this would not be unusual because 46% is only 1.2 standard errors from 40%

Step-by-step explanation:

Consider the provided information.

The standard error is approximately 5%

Standard error(SE)=0.05

As we know

Here x=46%=0.46 and μ=40%=0.40

Now use the formula:

Substitute the respective values in the above formula.

Hence, this would not be unusual because 46% is only 1.2 standard errors from 40%

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

hi! i think the answer is 1/2 : )