Name the postulate or theorem you can use to prove ade=eba?

(c)  Δ ADE ≅  Δ EBA  by AAS Theorem

Step-by-step explanation:

Here, in Δ ACE

AC  =  CE (given)

Also, ANGLES OPPOSITE TO EQUAL SIDES ARE EQUAL.

⇒ ∠E  = ∠A   (1)

Now, in Δ ADE and Δ EBA

∠E  = ∠A  (from above)

∠ADE  = ∠ABC ( right angle)

 AE = AE (common side)

hence, Δ ADE ≅  Δ EBA  by AAS Theorem

As,  by AAS Theorem (ANGLE ANGLE SIDE)

Two triangle said said to be congruent if 2 angles and 1 side of one triangle is equal to 2 corresponding angles and 1 corresponding side of the other triangle.

Hence, Δ ADE ≅  Δ EBA  by AAS Theorem

answer: the answer is d

8(1/6)

step-by-step explain:

49/6= 48

8 (1/6)