Find the image vertices for a dilation with center (0,0)
and a scale factor of 4.

* show steps if you can. if not, it’s fine

Image vertices are : A' = (-12 , 4) ; B' = (16 , -12) ; C' = (8 , 12) ; D' = (-4 , 16)

Step-by-step explanation:

Given :

Scale Factor = 4

Vertices given in the above graph :

A = (-3 , 1) ; B = (4 , -3) ; C = (2 , 3) ; D = (-1 , 4)

Calculation :

To find the image vertices for a dilation with center (0 , 0) we have to multiply the vertices by scale factor 4.

So the image vertices are :

A' = (-12 , 4) ; B' = (16 , -12) ; C' = (8 , 12) ; D' = (-4 , 16)

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The resultant image vertices will be,

A' = (-12 ,4) ;  B' = (16 , -12) ; C' = (8, 12) and D'= (-4, 16)

Step-by-step explanation:

The co-ordinates of the given image vertices are,

A = (-3 , 1) ; B = (4 ,-3); C = (2, 3) and D = (-1, 4)

If the image is dilated with center (0, 0) and a scale factor of 4, then in the resultant image, all the co-ordinates will be multiplied by a factor of 4.

So, the resultant image vertices will be,

A' = (-12 ,4) ;  B' = (16 , -12) ; C' = (8, 12) and D'= (-4, 16)

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺

step-by-step explanation:

infinity is the answer