Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. a. when designing a study to determine this population proportion, what is the minimum number of drivers you would need to survey to be 95% confident that the population proportion is estimated to within 0.01? (round your answer up to the nearest whole number.)b. if it was later determined that it was important to be more than 95% confident and a new survey was commissioned, how would that affect the minimum number you would need to survey?

At least 9604 drivers need to be surveyed  to be 95% confident that the population proportion is estimated to within 0.01.

If confidence level is chosen higher than 95% then minimum sample size requried in the survey increases

Step-by-step explanation:

The following formula is used to compute the minimum sample size required to estimate the population proportion  within the required margin of error:

n≥ p×(1-p) × where

Then,

n≥0.5×0.5 × ≈ 9604

If confidence level is chosen higher than 95% then the z value in the equation would be bigger than 1.96. Therefore minimum sample size requried in the survey increases.

.25

step-by-step explanation:

the final amount you will pay is $68.04.

the tip is determined by the pre-tax amount, so we calculate the tip based on the original bill, not after we've added sales tax.

to find the tip:

we can divide 54.00 by 100 to get 1% of 54. then we multiply that by 18.

54 / 100 = .54

.54 x 18 = 9.72

tip = 9.72$

to find the tax:

we can divide 54.00 by 100 to get 1% of 54. then we can multiply that by 8 to get 8%.

54 / 100 = .54

.54 x 8 = 4.32

tax= 4.32

now we can add the tip and tax to the bill to get our total.

54 + 9.72 + 4.32 = 68.04

total: $68.04

step-by-step explanation: