Suppose that in a random selection of 100 colored candies, 26% of them are blue. the candy company claims that the percentage of blue candies is equal to 27%. use a 0 .05 significance level to test that claim. identify the test statistic for this hypothesis test. find the p-value for this hypothesis test

 a) -0.2252, b) 0.8219

Step-by-step explanation:

Since we have given that

Sample size n = 100

Probability that candies are blue = p= 0.26

Probability that company claims that it is blue candy = P = 0.27

So, Q = 1-P= 1-0.27 = 0.73

So, Null hypothesis :

Alternate hypothesis :

So, the test statistic would be

Since α = 0.05

So, critical value of z = 1.96

p-value = P(Z>Z(calculated)

Using the excel function , we get that

Hence, a) -0.2252, b) 0.8219

300

step-by-step explanation:

28-600w < 300

28-600w > 300

600-28w < 300

600-28w > 300

the 3rd on is correct

step-by-step explanation: