The weights of newborn babies are distributed normally, with a mean of approximately 105 oz and a standard deviation of 10 oz. if a newborn baby is selected at random, what is the probability that the baby weighs more than 75 oz

0.9987

Step-by-step explanation:

Given : The weights of newborn babies are distributed normally, with a mean of approximately 105 oz and a standard deviation of 10 oz.

i.e.  and

Let x represents the weights of newborn babies.

If a newborn baby is selected at random, then the probability that the baby weighs more than 75 oz will be :-

  [using z-value table]

Hence, the required probability = 0.9987

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions