Fyling against the wind, an airplane travels 4779 kilometers in 9 hours. flying the same wind, the sampe plane travels 6060 kilometers in 6 hours. what is the rate of the plane still in the air abd what is the rate if the winf?

Rate of plane in still air: 770.5 km/hr

Rate of wind: 239.5 km/hr

Step-by-step explanation:

Let x represent speed of plane in still air and w represent speed of wind.

Speed of plane with wind would be .

Speed of plane against wind would be .

We will use following formula to solve our given orblem.

We have been given that flying against the wind, an airplane travels 4779 kilometers in 9 hours. We can represent this information in an equation as:

     (Dividing by 9)

We are also told that flying with the wind, the same plane travels 6060 kilometers in 6 hours. We can represent this information in an equation as:

      (Dividing by 6)

Upon adding equation (1) and (2), we will get:

Therefore, the rate of the plane in still air is 770.5 kilometers per hour.

To find the rate of the wind, we will substitute in equation (1) as:

Therefore, the rate of the wind is 239.5 kilometers per hour.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0