Answer each part for the following context-free grammar g. r → xrx | s s → atb | bta t → xtx | x | ε x → a | b a. what are the variables of g? b. what are the terminals of g? c. which is the start variable of g? d. give three strings in l(g). e. give three strings not in l(g). f. true or false: t ⇒ aba. g. true or false: t ∗ ⇒ aba. h. true or false: t ⇒ t.

Divide 40%5 and your answer is 8

It is 5.8 you add all of the up to equat 180 then solve the equation

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to