Mathematics, 20.11.2019 16:31, Jspice1996
Can polynomials have odd roots (like f(x)= cube root of i’ll give branliest!
Answers: 2
![x = \sqrt[3]{29}](/tpl/images/0383/0357/c5bbb.png)
(cube root of 29) and the other two roots are complex or imaginary roots.
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Can polynomials have odd roots (like f(x)= cube root of i’ll give branliest!...
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