1. suppose that the cost of producing x tablets is defined by
c(x) - 200 + 10x + 0.2x, where x represents the number on
produced. the graph below represents the function.
presents the number of tablets
b (25,575)
(20,480)
(15,395)
part a: complete the boxes to label the graph.
part b: find the average rate of change over the interval [a, b].
part c: find the average rate of change over the interval [b, c).

we are given

part-A:

Since, x is number of tablets

C(x) is cost of producing x tablets

so, vertical box is C(x)

so, we write in vertical box is "cost of producing x tablets"

Horizontal box is x

so, we write in horizontal box is "number of tablets"

part-B:

we have to find average on [a,b]

we can use formula

we are given point as

a: (15 , 395)

a=15 and C(15)=395

b: (20, 480)

b=20 , C(20)=480

now, we can plug values

Answer

part-c:

we have to find average on [b,c]

we can use formula

we are given point as

b: (20, 480)

b=20 , C(20)=480

c:(25,575)

c=25 , C(c)=575

now, we can plug values

15% chance.

step-by-step explanation:

3/10 times, the 5 year old will get a tablet. 5/10 times, the 13 yer old will get a tablet. multiply both fractions to get 15/100 times, both would have a tablet.

answer: 80,000

step-by-step explanation:

the population doubles every day.

10,000*2=20,000 day 4

20,000*2=40,000 day 5

40,000*2=80,000 day 6