If a jury of 12 people is to be selected randomly from a pool of 15 potential jurors, and the jury pool consists of 2/3 men and 1/3 women, what is the probability that the jury will comprise at least 2/3 men?
a. 24/91
b. 45/91
c. 2/3
d. 67/91
e. 84/91

D.

Step-by-step explanation:

Given,

Total number of jurors = 15,

Out of which 2/3 are men and 1/3 are women,

So, total men = = 10,

And, total women = 15 - 10 = 5,

The people have to select = 12,

So, the total ways of selecting 12 people =

Now, 2/3 of 12 =  = 2 × 4 = 8,

Thus, there would be at least 8 men.

Now, the possible ways of selecting at least 8 men = 8 men 4 women + 9 men 3 women + 10 men 2 women

= 225 + 100 + 10

= 335

Hence, the probability that the jury will comprise at least 2/3 men

OPTION D is correct.

step-by-step explanation:

left be aligning the decimal points is required to not required see the number of digits to the right

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube