Transforming between two encodings for boolean vectors. a boolean n-vector is one for which all entries are either 0 or 1. such vectors are used to encode whether each of n conditions holds, with ai = 1 meaning that condition i holds. another common encoding of the same information uses the two values −1 and +1 for the entries. for example the boolean vector (0,1,1,0) would be written using this alternative encoding as (−1, +1, +1, −1). suppose that x is a boolean vector with entries that are 0 or 1, and y is a vector encoding the same information using the values −1 and +1. express y in terms of x using vector notation. also, express x in terms of y using vector notation.

See below

Step-by-step explanation:

We are looking for a function f such that

f(0) = -1

f(1) = 1

One of the simplest ones is the line that joins (0, -1) and (1,1)

y = 2x -1

So, if we have a Boolean n-vector in the first codification (0,1)

then

is the expression of Y in terms of X.

Similarly, the inverse function of the line, x = (y+1)/2, does the inverse transformation.

That is to say, if we have a vector  

in the second codification -1 and +1

is the expression of X in terms of Y

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !

step-by-step explanation: