What are the factors of the polynomial function? !

use the rational root theorem to determine the factors.

f(x) = x^3 + 6x² + 3x - 10

drag each factor of f(x) into the box.

factors of f(x)

(x-1) (x + 1) (x - 2) (x + 2) (x - 5) ( x + 5 ) ( x - 10) (x + 10)

(x-1)(x+2)(x+5)

Step-by-step explanation:

a is the right answer

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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