Arunning store offers a 15% discount on
buying 2 pairs of running shoes. jane buys two
pair of shoes that each cost the same and paid a
total bill of $110.50, after the discount. what
was the cost of each pair of shoes before the
discount?

The cost of each pair of shoes before the discount=$67.65

Step-by-step explanation:

Step 1

Use the expression below to determine original cost of the 2 pairs of shoes as follows;

A=O-R

where;

A=total bill after discount

O=original cost of 2 pairs of shoe

R=discount amount

In our case;

A=$110.50

O=unknown=x

R=15% of O=(15/100)×x=0.15 x

replacing;

115=x-0.15 x

115=0.85 x

x=115/0.85

x=135.294

Original cost of the 2 pairs of shoes=$135.294

Original cost of a pair of shoes=135.294/2=$67.65

The cost of each pair of shoes before the discount=$67.65

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!

exactly you go it

step-by-step explanation: