He american heart association is about to conduct an anti-smoking campaign and wants to know the fraction of americans over 45 who smoke. step 2 of 2: suppose a sample of 830 americans over 45 is drawn. of these people, 631 don't smoke. using the data, construct the 85% confidence interval for the population proportion of americans over 45 who smoke. round your answers to three decimal places.

The 85% confidence interval is (0.2187, 0.2613).

Step-by-step explanation:

We have a large sample of size n = 830 Americans over 45. We have observed that 631 people don't smoke. Let p be the population proportion of Americans over 45 who smoke. An point estimate of p is and an estimate of the standard deviation of is = 0.0148. Therefore, because we have a large sample, the 85% confidence interval for the population proportion is given by where is the 7.5th quantile of the standard normal distribution, i.e., -1.4395. Therefore the 85% confidence interval is or equivalently (0.2187, 0.2613).

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation:

17

step-by-step explanation:

51/3=17

thus 17 is your answer.