30 points! fill in the blanks ! i'll give you brainliest for correct

weights of the vegetables in a field are normally distributed. from a sample carl cornfield determines the mean weight of a box of vegetables to be 180 oz. with a standard deviation of 8 oz. he wonders what percent of the vegetable boxes he has grouped for sale will have a weight more than 196 oz.

carl decides to answer the following questions about the population of vegetables from these sample statistics:

carl calculates the z-score corresponding to the weight 196 oz.

using the table (column .00), carl sees the area associated with this z-score is 0.

carl rounds this value to the nearest thousandth or 0.

since 0.50 represents the part of the curve to the right of the mean (a z-score of 0) and the z-score carl just calculated represents the part of the curve from the mean to the point representing 196 oz., then carl can find the part of the curve to the right of 196 oz. by subtracting.

so, carl subtracts 0.50 - 0. = %

this is the percent of vegetable boxes that weigh more than 196 oz.