Evaluate the following equation: integral from 3 to infinity: 1/(x-2)^(3/2) dx

The formula in solving the integral of the infinity of 3 is  ∫3∞?(1)÷((x−2)(3/2))dx

Substitute the numbers given then solve

limn→inf∫3n(1/((n−2)(3/2))dn

limn→inf[−2/(n−2−−−−−√)−(−2/3−2−−−−√)

=0+2=2

Solve for the integral of 2 when 2 is approximate to 0. Transpose 2 from the other side to make it -2

∫∞3(x−2)−3/2dx=(x−2)−1/2−1/2+C

(x−2)−1/2=1x−2−−−−√

0−(3−2)−1/2−1/2=2

2.83941151 would be the answer you're looking for! : )

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