Suppose that the average number of accidents occurring on a highway each day is 3.5. find the probability that at least two accidents occur today. find the probability that at most one accident occurs today.

0.1359

Step-by-step explanation:

This is a Poisson distribution. The formula for calculating Poisson distribution is given as :

P (X = x) =

λ = 3.5

To find the probability that at most one accident occur today implies that , accident might not happen at all , the maximum accident that can happen is 1, substituting this into the formula , we have

P(X=0) =

P(X=0) = 0.0302

P(X=1) =  

P(X=1) = 0.1057

Therefore , the probability that at most one accident occurs today.

= 0.0302 + 0.1057

= 0.1359

P(x=2) =  

P(X=2) = 0.1850

what is the original number? you forgot to add it.

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all