Which is the graph of f(x) = (2)-x ?
on a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases into quadrant 1. it crosses the y-axis at (0, 1).

on a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases into quadrant 2. it crosses the y-axis at (0, 1).

on a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases into quadrant 2. it crosses the y-axis at (0, 2).

We will choose option 2.

Step-by-step explanation:

The given function is

So, from the above equation it is clear that as x increases in the first quadrant the value of f(x) tends to zero and increases into second quadrant.{ Since x is negative in the second quadrant}

Again, for x = 0, y becomes 1, i.e. the function crosses the y axis at (0,1).

Therefore, on a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases into quadrant 2. (0, 1) point is the point of intersection with the y-axis.  

So, we will choose option 2. (Answer)

b

step-by-step explanation: