Atrain travels from new york city to washington, dc, and then back to new york city. the table shows the number of tickets purchased for each
leg of the trip. the cost per ticket is the same for each leg of the trip.

destination 1: washington, d. c.
coach tickets 1: 150
business class tickets 1: 80
money collected (dollars) 1: 22,860

destination 2: new york city
coach tickets 2: 170
business class tickets 2: 100
money collected (dollars) 2: 27,280

write the equations to the system that would explain your answer
use c for the cost of a coach ticket and b for the cost of a business class ticket
destination washington dc. equation:
destination new york city equation:

A system of equation is simply a collection of multiple equations

The system of equations is 150c + 80b = 22860, and 170c + 100b = 27280

From the question, we understand that:

This means that, the equation of destination 1 would be

150c + 80b = 22860

While the equation of destination 2 would be

170c + 100b = 27280

Hence, the system of equations is 150c + 80b = 22860, and 170c + 100b = 27280

Read more about systems of equations at:

link

 $74

Step-by-step explanation:

Let C represent the cost of a coach ticket

Let B represent the cost of a business ticket

Washington: 150C +  50B = 18,450

NY City:         170C + 100B = 27,280

Solve the system using the Elimination method:

-2(150C +  80B = 18,450)   →   -300C - 100B = -36,900

1(170C + 100B = 27,280)   →     170C + 100B =  27,280  

                                                -130C             =  - 9,620

                                              ÷ -130                 ÷   -130    

                                                         C            =      74

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: