Find the point, m, that divides segment ab into a ratio of 5: 6 if a is at (0,22) and b is at (11,0).

(5,12)

Step-by-step explanation:

The co-ordinates of point M is

When provided with points A(x1, y1) and B(x2,y2) then to find the coordinates of the points that divide the line segment AB internally we use the formula

Similarly, for the same points but when it’s divided externally we use the formula

For this case, we use the first formula

M=5 and n=6 hence m+n=11

Total ratio is 5+6=11

Difference in x direction=11-0=11 points

Difference in y direction=0-22=-22 points

Point M=5/11(11, -22)+ point A

Point M=(5,-10)+(0+22)=(5,12)

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5