Right triangle abc has legs ac and bc of lengths 16mi and 24mi accordingly. find the distance of point b from the line that contains the median am.

9.6 mi

Step-by-step explanation:

in right triangle ABC,

AC = 16 mi

BC = 24 mi

If AM is the median, then CM = MB = 12 mi

Consider triangles CAM and EBM. In these triangles,

So, triangles CAM and EBM are similar by AA postulate.

Similar triangles have proportional corresponding sides, so

By the Pythagorean theorem,

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

at least two

step-by-step explanation: