Roberto's toy car travels at 30 centimeters per second (cm/sec) at high speed and 20 cm/sec at low speed. if the car travels for 20 seconds at high speed and then 30 seconds at low speed, what distance would the car have traveled

1200 centimeters in total, 600 seperate

Step-by-step explanation:

30 cm/second at high speed for 20 seconds = 30 * 20 = 600.

20 cm/second at low speed for 30 seconds = 20 * 30 = 600.

600 + 600 = 600 * 2 = 1200 cm in total

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

no

step-by-step explanation: