You throw three darts in a numbered region of the dart board that has the scores of 2, 5, and 8. how many different sums are possible for the three darts

12 different sums

Step-by-step explanation:

there's three darts and three numbers.

if you use the factorial 3! for both the number of darts and the score numbers and add the two together, you would get twelve :

( 3! = 3*2*1 = 6 ) * 2

6 + 6 = 12

or you could just write out all the combinations like this :

2+2+2

2+2+5

2+5+5

2+5+8

2+8+8

5+5+2

5+5+5

5+5+8

5+8+8

8+8+2

8+8+5

8+8+8