Hello everyone! can someone me with this work, it is very very important to me. will be appreciated very much : )

find the equation of the line that is parallel to the line y = 5x + 4 and has the same y-intercept as y = 3x - 2

find the equation of the line that is perpendicular to the line 5x + y = 4 and has the same y-intercept as 3x + 2y = 16

Step-by-step explanation:

(1) Since the line is parallel to y = 5x + 4 , it means that they have the same slope , which is 5 and it was said that it has the same y - intercept as y = 3x -2 , which is -2

using the formula for equation of line , y = mx + c , then the equation of the line will be

y = 5x - 2

(2) Since the line is perpendicular to 5x + y = 4 , if M1 is the slope of the given line, and M2 is the slope of the line we are looking for , since they are perpendicular , it means that M1 = -1 / M2.

To find the slope of the given line , we will need to make y the subject of the formula, that is

y = - 5x + 5 , this means that the slope of the second line is 1/5

and the intercept is 16 , so the equation of the line is

y = 1/5x + 16

i dont know

step-by-step explanation:

b i think

step-by-step explanation:

not really sure