Ahot air balloon is tethered to the ground by rope that is 200 feet long. the balloon floats into the sky at a rate of 4 feet per second. the equation y=4x gives the height, y, of the balloon x seconds after leaving the ground.

graph the function
what’s the domain?
what’s the range?
interpret the x and y intercepts.

Step-by-step explanation:

y is the height of the balloon.  x is the time in seconds.

The balloon starts on the ground, so the smallest value of y is 0.  We know the rope is 200 feet long, so the biggest value of y is 200.  So the range is 0 ≤ y ≤ 200.

Find the value of x at each end of the range.

When y = 0:

0 = 4x

x = 0

When y = 200:

200 = 4x

x = 50

So the domain is 0 ≤ x ≤ 50.

The x and y-intercept is (0, 0).  This means the balloon is initially on the ground.

Graph: desmos.com/calculator/eaavtvbuxm

x= 149. 24+7=31. 180-31=149

your welcome

a is the right answer