The data below are a variation of the data presented in exercise 12-4 age (x) 50 34 12 36 18 6.20 1.40 6.05 3.30 8.05 (a) calculate the correlation coefficient by hand. use formula (12.1) on page 488. (a negative value should be indicated by a minus sign. round your final answer to 3 decimal places). calc

- 0.352

Step-by-step explanation:

Data provided in the question:

Age (X)   50       34       12       36       18

       (Y)  6.20    1.40    6.05    3.30    8.05

Now,

correlation coefficient, r =

Here,

∑(X - Mx)² = SSx

∑(Y - My)² = SSy

Mx: Mean of X Values  = = 30

My: Mean of Y Values  = = 5

X - Mx & Y - My: Deviation scores

(X - Mx)² & (Y - My)²: Deviation Squared

(X - Mx)(Y - My): Product of Deviation Scores

Thus,

( X - Mx )         ( Y - My )          (X - Mx)²         (Y - My)²         (X - Mx)(Y - My)

 20.0                1.20                 400.0             1.44                      24.0

 4.0                 -3.60                  16.0                 12.96                   -14.4

- 18.0                 1.05                  324.0             1.102                    -18.9

 6.0                 -1.70                  36.0                2.89                    -10.2

- 12.0                 3.05                144.0               9.303                    -36.6

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∑(X - Mx)²  = 920.0

∑(Y - My)² = 27.695

∑(X - Mx)(Y - My)  = -56.1

thus,

r =

or

r = - 0.352

yo answer should be 6 if im not mistaken

step-by-step explanation: