The mean response time of a species of pigs to a stimulus is 0.8 seconds. twenty-eight pigs were given 2 oz of alcohol and then tested. if their sample average response time was 1.0 seconds with a sample standard deviation of 0.3 seconds, can we conclude that alcohol affects the mean response time? use the 5 percent significance level.

Let be the mean response time of a species of pigs to a stimulus.

As per given , we have

Since , the alternative hypothesis is two-tailed and population standard deviation is unknown , so we perform two-tailed t-test.

Also, we have n= 28

Sample mean =

sample standard deviation= s= 0.3

Test statistic :

P-value :  

     [using p-value table for t]

Decision : Since p-value < 0.05 ( significance level ), so we reject the null hypothesis .

Conclusion : We have enough evidence to accept that alcohol affects the mean response time.

eve and marks ratios are equivalent

step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true