Me solve

write an equation of the line passing through point p(-1,3) that is perpendicular to y=4x-7

Two lines are perpendicular if their slope m and m' satisfy the equation

The slope of the given line is 4, because the line is written in the slope-intercept y=mx+q, where m is the slope.

So, the perpendicular slope is

So, we want a line with slope -1/4 and passing through (-1,3). We can use the formula

for the line passing trough (a,b) with slope m:

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

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im not sure