Can someone with the ones that aren’t answered?

(i love unit circles!)

C: -1

D: -1/2

G: -2

H: square root 3 over 2

I: negative square root 2 over 2

Step-by-step explanation:

okay i'm not sure if i'll be able to explain it well here but i can try. so sin is y, cos is x yadda yadda. i use something called the hand trick to find the coordinates and i'll include a photo. essentially, if you have sin of 11 pi over 6, let's say, you ignore the numerator first and look at the denominator which is 6. so you go to your ring finger on your hand and fine how many fingers are below that, which is 1. take the square root of 1 and put it over 2 and boom that's your coordinate for sin. to see if it's negative, look at the numerator and see what quadrant it's in. in this case, it's in the 4th quadrant which is a negative y value. we'll do another. cos of negative 11 pi over 6. so negative 11 pi over six is the same thing as going just pi over 6. so go on your hand and find where something over 6 is, which is your ring finger. cos is above so find how many fingers above you have, which is 3. take the square root of that and put it over 2. to see if it's negative, check the quadrant. pi over 6 is in the first so it's positive. for secant, find cosine and your answer is the inverse. for cosecant, find sine and your answer is the inverse. this is a very simplified answer and i hope you understand it well? you can message me for more details if you are confused.

hope this helps!

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .