What quadratic equation has -4 and 2/3 as it’s roots

3x^2 + 10x - 8 = 0.

Step-by-step explanation:

In factor form it would be:

(x + 4)(3x - 2) = 0  (because x + 4 = 0 gives x = -4 and 3x - 2 = 0 gives x = 2/3);

Now change to standard form:

= 3x^2 - 2x + 12x - 8 =0

= 3x^2 + 10x - 8 = 0.

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.