The paraboloid z = 6 − x − x² − 7y² intersects the plane x = 1 in a parabola. find parametric equations in terms of t for the tangent line to this parabola at the point (1, 2, −24). (enter your answer as a comma-separated list of equations. let x, y, and z be in terms of t.)

First you need to know is the equation of the parabola in order to get the equation of the tangent line. So we replace x = 1 in the paraboloid equation and we get:

So now that we have the parabola's equation, we calculate the slope of the tangent line deriving and replacing with the point (2,-24) (this point doesn't have the x term because we already used it and we are in terms of y and z).

Now we have the next equation:

In order to calculate the term 'b', we replace (y,z) with the point (2,-24):

Then, we finally get the tangent line equation as follow:

Finally, in order to convert the variables in terms of t, we just replace 't' in any variable. In this case I will replace in y because is convenient.

y = t,

z = -28t+32,

x = 1 (because is always a constant so It doesn't depend of any variable)

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°