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∆abc is translated 2 units down and 1 unit to the left. then it is rotated 90° clockwise about the origin to form ∆a′b′c′.

the coordinates of vertex a′ of ∆a′b′c′ are .

the coordinates of vertex b′ of ∆a′b′c′ are .

the coordinates of vertex c′ of ∆a′b′c′ are .

Answer with Step-by-step explanation:

We are given that a triangle ABC in which the vertices of A is at (0,0), B is at (1,3) and C is at (1,1).

We have to find the coordinates of triangle AB'C'created after translation 2 units down and 1 unit left and then rotated 90 clockwise about the origin .

The rule of transformation when the coordinates of triangle ABC is translated 2 units down and 1 unit left is given by

Apply this transformation rule then, we get

The new vertices of triangle ABC is given by

The rule of  rotation of 90 degree clockwise about the origin is given by

Apply this rule, then we get a triangle A'B'C'

The vertices A'=(-2,-(-1))=(-2,1)

Hence, the coordinates of vertex A' of triangle A'B'C' are (-2,1).

The coordinates of vertex of B' of triangle A'B'C' are (1,0).

The coordinates of vertex of C' of triangle A'B'C' are (-1,0).

42

step-by-step explanation:

256/6=42