18)
draw a line segment of any length and label it po.
if you were to construct a line segment congruent to pq, what would be your first step?
a)
put one end of the compass on point p and the other end on point q.
measure pq using a ruler.
draw an arc the size of pq below the segment.
draw a new segent below the line the same length as po.

I'd say

Put one end of the compass on point P and the other end on point Q.

This way, you can construct (part of) a circumference with radius PQ with center P.

If you connect point P with any point on the circumference, this segment will be another radius of the circumference, and thus congruent to PQ.

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: